Putting the Triangle Centroid method to work
Vertices (0,0),(6,0),(3,9) have centroid (3,3).
Average three vertices to locate the intersection of a triangle’s medians. A checkable formula accompanies centroid coordinates instead of leaving an unexplained number.
Vertices (0,0),(6,0),(3,9) have centroid (3,3).
The centroid is ((x₁+x₂+x₃)/3,(y₁+y₂+y₃)/3) and divides every median in a 2:1 ratio from vertex to midpoint.
It is the balance point of a uniform triangular lamina and a common reference in meshes and coordinate geometry.
The Triangle Centroid meaning depends on Vertex 1 x. The Triangle Centroid meaning also depends on Vertex 1 y. Carry those Triangle Centroid roles into any later Triangle Centroid work.
Average the three x-coordinates and separately average the three y-coordinates. To continue from Triangle Centroid, try triangle area.
Collinear points still have an average coordinate but do not define a nondegenerate triangle; interpret that case carefully. If the Triangle Centroid assumptions do not fit, consider side midpoint.
Sketch Vertex 1 x before running Triangle Centroid. Place Vertex 1 y on the Triangle Centroid sketch and confirm its unit.
Test a symmetric Triangle Centroid case. In that Triangle Centroid case, compare Vertex 1 y with the expected Triangle Centroid scale.
Preserve Vertex 1 x when checking the Triangle Centroid output. Keep Vertex 1 y under the same convention and estimate Centroid coordinates. A controlled change to Vertex 2 x should move the Triangle Centroid Centroid coordinates in a mathematically consistent direction.
Keep extra digits in Centroid coordinates until the next step is known. Early rounding can obscure whether Vertex 1 x and Vertex 1 y satisfy the Triangle Centroid relation. Round the final Centroid coordinates once, using precision appropriate to the original Triangle Centroid data.
Record the original Vertex 1 x before changing Triangle Centroid. Keep Vertex 1 y with that record and attach its own Centroid coordinates. A later Triangle Centroid trial then remains distinguishable from the first calculation.
Yes for a nondegenerate triangle.
No.
2:1 from the vertex.
Only for special symmetric triangles.